What are the solutions to the equation 5x^2-8x+25=0 ?

The solutions to the equation 5x^2-8x+25=0 are x= 4/5+i(sqrt(109))/5 ,x= 4/5-i(sqrt(109))/5

Find the zeros of 5x^2-8x+25=0

The zeros of 5x^2-8x+25=0 are x= 4/5+i(sqrt(109))/5 ,x= 4/5-i(sqrt(109))/5

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5 x^{2} - 8 x + 25 = 0

x = \frac{4}{5} + i \frac{109}{5}, x = \frac{4}{5} - i \frac{109}{5}

Solution steps

5 x^{2} - 8 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 5 \cdot 25}{2 \cdot 5}

Simplify

(- 8)^{2} - 4 \cdot 5 \cdot 25 : 2109 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 109 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 109 i}{2 \cdot 5}, x_{2} = \frac{- ( - 8 ) - 2 109 i}{2 \cdot 5}

x = \frac{- ( - 8 ) + 2 109 i}{2 \cdot 5} : \frac{4}{5} + i \frac{109}{5}

x = \frac{- ( - 8 ) - 2 109 i}{2 \cdot 5} : \frac{4}{5} - i \frac{109}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5} + i \frac{109}{5}, x = \frac{4}{5} - i \frac{109}{5}

x^{2} - 8 x + 12 = 0

x^{2} + 1 = 0

(x - 4) (1 + x) = 0

- 3 x^{2} + 5 x - 1 = 5 x^{2} - 8 x - 3

x^{2} - 25 x + 9

What are the solutions to the equation 5x^2-8x+25=0 ?
The solutions to the equation 5x^2-8x+25=0 are x= 4/5+i(sqrt(109))/5 ,x= 4/5-i(sqrt(109))/5
Find the zeros of 5x^2-8x+25=0
The zeros of 5x^2-8x+25=0 are x= 4/5+i(sqrt(109))/5 ,x= 4/5-i(sqrt(109))/5