What are the solutions to the equation 6q^2+10q+25=5q^2 ?

The solutions to the equation 6q^2+10q+25=5q^2 are q=-5

Find the zeros of 6q^2+10q+25=5q^2

The zeros of 6q^2+10q+25=5q^2 are q=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 q^{2} + 10 q + 25 = 5 q^{2}

q = - 5

Solution steps

6 q^{2} + 10 q + 25 = 5 q^{2}

Move

5 q^{2}

to the left side

q^{2} + 10 q + 25 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

q_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

q = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

q = - 5

The solution to the quadratic equation is:

q = - 5

19 v^{2} - v - 2 = 4 v^{2}

2 x (x - 2) = 200

(1 - x)^{2} = e^{3}

- k^{2} - 3 k - 2 = - 5 k^{2}

x^{2} = 10 - 3 x

What are the solutions to the equation 6q^2+10q+25=5q^2 ?
The solutions to the equation 6q^2+10q+25=5q^2 are q=-5
Find the zeros of 6q^2+10q+25=5q^2
The zeros of 6q^2+10q+25=5q^2 are q=-5