What are the solutions to the equation 16r^2=4a^2 ?

The solutions to the equation 16r^2=4a^2 are r= a/2 ,r=-a/2

Find the zeros of 16r^2=4a^2

The zeros of 16r^2=4a^2 are r= a/2 ,r=-a/2

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16 r^{2} = 4 a^{2}

r = \frac{a}{2}, r = - \frac{a}{2}

Solution steps

16 r^{2} = 4 a^{2}

Divide both sides by

16

r^{2} = \frac{a ^{2}}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{a ^{2}}{4}, r = - \frac{a ^{2}}{4}

Simplify

\frac{a ^{2}}{4} : \frac{a}{2}

Simplify

- \frac{a ^{2}}{4} : - \frac{a}{2}

r = \frac{a}{2}, r = - \frac{a}{2}

\frac{25}{6} x^{2} = \frac{8}{3}

9 x^{2} + 12 x + 11 = 6 x^{2}

- \frac{4}{7} x^{2} + 28 = 0

(1 - 4 x)^{2} + 5 = (2 - 3 x) (1 - 5 x)

- 2 x^{2} + 100 x = 0

What are the solutions to the equation 16r^2=4a^2 ?
The solutions to the equation 16r^2=4a^2 are r= a/2 ,r=-a/2
Find the zeros of 16r^2=4a^2
The zeros of 16r^2=4a^2 are r= a/2 ,r=-a/2