What are the solutions to the equation x^2-3x-19=0 ?

The solutions to the equation x^2-3x-19=0 are x=(3+sqrt(85))/2 ,x=(3-sqrt(85))/2

Find the zeros of x^2-3x-19=0

The zeros of x^2-3x-19=0 are x=(3+sqrt(85))/2 ,x=(3-sqrt(85))/2

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x^{2} - 3 x - 19 = 0

x = \frac{3 + 85}{2}, x = \frac{3 - 85}{2}

Decimal Notation

x = 6.10977 \dots, x = - 3.10977 \dots

Solution steps

x^{2} - 3 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 19) = 85

x_{1, 2} = \frac{- ( - 3 ) \pm 85}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 85}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 85}{2 \cdot 1}

x = \frac{- ( - 3 ) + 85}{2 \cdot 1} : \frac{3 + 85}{2}

x = \frac{- ( - 3 ) - 85}{2 \cdot 1} : \frac{3 - 85}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 85}{2}, x = \frac{3 - 85}{2}

(x - 4)^{2} - 10 = (x - 1)^{2} - x^{2}

x^{2} + x + 3

x^{2} + x + 6

4 w^{2} - 19 w + 21 = 2

y, x^{2} + y^{2} - 4 x + 6 y + 13 = 0

What are the solutions to the equation x^2-3x-19=0 ?
The solutions to the equation x^2-3x-19=0 are x=(3+sqrt(85))/2 ,x=(3-sqrt(85))/2
Find the zeros of x^2-3x-19=0
The zeros of x^2-3x-19=0 are x=(3+sqrt(85))/2 ,x=(3-sqrt(85))/2