What are the solutions to the equation s^2-s=0 ?

The solutions to the equation s^2-s=0 are s=1,s=0

Find the zeros of s^2-s=0

The zeros of s^2-s=0 are s=1,s=0

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s^{2} - s = 0

s = 1, s = 0

Solution steps

s^{2} - s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

s_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, s_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

s = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

s = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

s = 1, s = 0

16.7 - \frac{20 x ^{2}}{10} = 0

- x^{2} + 10 x + 25 = 0

10 = 3 Q^{2} - 18 Q + 5

s^{2} + 4 s + 13

4 x^{2} + 11 x - 108 = 0

What are the solutions to the equation s^2-s=0 ?
The solutions to the equation s^2-s=0 are s=1,s=0
Find the zeros of s^2-s=0
The zeros of s^2-s=0 are s=1,s=0