What are the solutions to the equation y^2=15y ?

The solutions to the equation y^2=15y are y=15,y=0

Find the zeros of y^2=15y

The zeros of y^2=15y are y=15,y=0

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y^{2} = 15 y

y = 15, y = 0

Solution steps

y^{2} = 15 y

Move

15 y

to the left side

y^{2} - 15 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 0 = 15

y_{1, 2} = \frac{- ( - 15 ) \pm 15}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 15 ) + 15}{2 \cdot 1}, y_{2} = \frac{- ( - 15 ) - 15}{2 \cdot 1}

y = \frac{- ( - 15 ) + 15}{2 \cdot 1} : 15

y = \frac{- ( - 15 ) - 15}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 15, y = 0

3 k^{2} + 9 k - 20 = 2 k

h^{2} + 19 h = 0

3 x^{2} - 10 x = - 7

y^{2} = - 15

2 x^{2} + 8 x + 11 = 0

What are the solutions to the equation y^2=15y ?
The solutions to the equation y^2=15y are y=15,y=0
Find the zeros of y^2=15y
The zeros of y^2=15y are y=15,y=0