What are the solutions to the equation roots x^2-10x+26 ?

The solutions to the equation roots x^2-10x+26 are x=5+i,x=5-i

Find the zeros of roots x^2-10x+26

The zeros of roots x^2-10x+26 are x=5+i,x=5-i

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roots

x^{2} - 10 x + 26

x = 5 + i, x = 5 - i

Solution steps

x^{2} - 10 x + 26

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 10 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 26 : 2 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 i}{2 \cdot 1} : 5 + i

x = \frac{- ( - 10 ) - 2 i}{2 \cdot 1} : 5 - i

The solutions to the quadratic equation are:

x = 5 + i, x = 5 - i

(x + 5)^{2} + 127 = 6

4 (x^{2} - 5) + 5 = - 3

7 x^{2} - 19 x - 6 = 0

4 x^{2} - 5 x = 6

s^{2} + 1.2 s + 1

What are the solutions to the equation roots x^2-10x+26 ?
The solutions to the equation roots x^2-10x+26 are x=5+i,x=5-i
Find the zeros of roots x^2-10x+26
The zeros of roots x^2-10x+26 are x=5+i,x=5-i