What are the solutions to the equation 3(x^2-6)-2=1 ?

The solutions to the equation 3(x^2-6)-2=1 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 3(x^2-6)-2=1

The zeros of 3(x^2-6)-2=1 are x=sqrt(7),x=-sqrt(7)

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3 (x^{2} - 6) - 2 = 1

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

3 (x^{2} - 6) - 2 = 1

Move

2

to the right side

3 (x^{2} - 6) = 3

Divide both sides by

3

x^{2} - 6 = 1

Move

6

to the right side

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

3 x^{2} + 24 x = - 39

y^{2} + 10 y + 4 = 0

x^{2} + 15 x + 21 = 0

p^{2} + 9 p + 3 = - 4 p^{2}

y^{2} + 8.19 y - 15 = 0

What are the solutions to the equation 3(x^2-6)-2=1 ?
The solutions to the equation 3(x^2-6)-2=1 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 3(x^2-6)-2=1
The zeros of 3(x^2-6)-2=1 are x=sqrt(7),x=-sqrt(7)