What are the solutions to the equation 34y^2-835y+4875=0 ?

The solutions to the equation 34y^2-835y+4875=0 are y=15,y= 325/34

Find the zeros of 34y^2-835y+4875=0

The zeros of 34y^2-835y+4875=0 are y=15,y= 325/34

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34 y^{2} - 835 y + 4875 = 0

y = 15, y = \frac{325}{34}

Decimal Notation

y = 15, y = 9.55882 \dots

Solution steps

34 y^{2} - 835 y + 4875 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 835 ) \pm ( - 835 ) ^{2} - 4 \cdot 34 \cdot 4875}{2 \cdot 34}

(- 835)^{2} - 4 \cdot 34 \cdot 4875 = 185

y_{1, 2} = \frac{- ( - 835 ) \pm 185}{2 \cdot 34}

Separate the solutions

y_{1} = \frac{- ( - 835 ) + 185}{2 \cdot 34}, y_{2} = \frac{- ( - 835 ) - 185}{2 \cdot 34}

y = \frac{- ( - 835 ) + 185}{2 \cdot 34} : 15

y = \frac{- ( - 835 ) - 185}{2 \cdot 34} : \frac{325}{34}

The solutions to the quadratic equation are:

y = 15, y = \frac{325}{34}

7 x - 4 = 2 x^{2}

x^{2} - 6 x = - 9

40 = x^{2}

xx + x + x = 24

3 x^{2} - 14 x - 1 = 0

What are the solutions to the equation 34y^2-835y+4875=0 ?
The solutions to the equation 34y^2-835y+4875=0 are y=15,y= 325/34
Find the zeros of 34y^2-835y+4875=0
The zeros of 34y^2-835y+4875=0 are y=15,y= 325/34