What are the solutions to the equation 3x^2-14x-1=0 ?

The solutions to the equation 3x^2-14x-1=0 are x=(7+2sqrt(13))/3 ,x=(7-2sqrt(13))/3

Find the zeros of 3x^2-14x-1=0

The zeros of 3x^2-14x-1=0 are x=(7+2sqrt(13))/3 ,x=(7-2sqrt(13))/3

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3 x^{2} - 14 x - 1 = 0

x = \frac{7 + 2 13}{3}, x = \frac{7 - 2 13}{3}

Decimal Notation

x = 4.73703 \dots, x = - 0.07036 \dots

Solution steps

3 x^{2} - 14 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 (- 1) = 413

x_{1, 2} = \frac{- ( - 14 ) \pm 4 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 4 13}{2 \cdot 3}, x_{2} = \frac{- ( - 14 ) - 4 13}{2 \cdot 3}

x = \frac{- ( - 14 ) + 4 13}{2 \cdot 3} : \frac{7 + 2 13}{3}

x = \frac{- ( - 14 ) - 4 13}{2 \cdot 3} : \frac{7 - 2 13}{3}

The solutions to the quadratic equation are:

x = \frac{7 + 2 13}{3}, x = \frac{7 - 2 13}{3}

24 x (x + 1) = 4 x^{2} - 7

4 x^{2} - 11 = 4 x

4 (x^{2} - 7) - 10 = - 13

28 q^{2} + 90 q = 0

3 x^{2} = 3 x + 5

What are the solutions to the equation 3x^2-14x-1=0 ?
The solutions to the equation 3x^2-14x-1=0 are x=(7+2sqrt(13))/3 ,x=(7-2sqrt(13))/3
Find the zeros of 3x^2-14x-1=0
The zeros of 3x^2-14x-1=0 are x=(7+2sqrt(13))/3 ,x=(7-2sqrt(13))/3