What are the solutions to the equation 28q^2+90q=0 ?

The solutions to the equation 28q^2+90q=0 are q=0,q=-45/14

Find the zeros of 28q^2+90q=0

The zeros of 28q^2+90q=0 are q=0,q=-45/14

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28 q^{2} + 90 q = 0

q = 0, q = - \frac{45}{14}

Decimal Notation

q = 0, q = - 3.21428 \dots

Solution steps

28 q^{2} + 90 q = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 \cdot 28 \cdot 0}{2 \cdot 28}

9 0^{2} - 4 \cdot 28 \cdot 0 = 90

q_{1, 2} = \frac{- 90 \pm 90}{2 \cdot 28}

Separate the solutions

q_{1} = \frac{- 90 + 90}{2 \cdot 28}, q_{2} = \frac{- 90 - 90}{2 \cdot 28}

q = \frac{- 90 + 90}{2 \cdot 28} : 0

q = \frac{- 90 - 90}{2 \cdot 28} : - \frac{45}{14}

The solutions to the quadratic equation are:

q = 0, q = - \frac{45}{14}

3 x^{2} = 3 x + 5

x^{2} + 16 = - 8 x

160 x^{2} + 18 x - 9 = 0

y, 4 y^{2} + x y - 2 x^{2} = 3

x^{2} + 5 x - 166.4 = 0

What are the solutions to the equation 28q^2+90q=0 ?
The solutions to the equation 28q^2+90q=0 are q=0,q=-45/14
Find the zeros of 28q^2+90q=0
The zeros of 28q^2+90q=0 are q=0,q=-45/14