What are the solutions to the equation x^2+16=-8x ?

The solutions to the equation x^2+16=-8x are x=-4

Find the zeros of x^2+16=-8x

The zeros of x^2+16=-8x are x=-4

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x^{2} + 16 = - 8 x

x = - 4

Solution steps

x^{2} + 16 = - 8 x

Move

8 x

to the left side

x^{2} + 16 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

x = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

160 x^{2} + 18 x - 9 = 0

y, 4 y^{2} + x y - 2 x^{2} = 3

x^{2} + 5 x - 166.4 = 0

2 x - 5 - 3 x^{2} = 0

(4 - x)^{2} = 1

What are the solutions to the equation x^2+16=-8x ?
The solutions to the equation x^2+16=-8x are x=-4
Find the zeros of x^2+16=-8x
The zeros of x^2+16=-8x are x=-4