What are the solutions to the equation 4x^2+17=20x ?

The solutions to the equation 4x^2+17=20x are x=(5+2sqrt(2))/2 ,x=(5-2sqrt(2))/2

Find the zeros of 4x^2+17=20x

The zeros of 4x^2+17=20x are x=(5+2sqrt(2))/2 ,x=(5-2sqrt(2))/2

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4 x^{2} + 17 = 20 x

x = \frac{5 + 2 2}{2}, x = \frac{5 - 2 2}{2}

Decimal Notation

x = 3.91421 \dots, x = 1.08578 \dots

Solution steps

4 x^{2} + 17 = 20 x

Move

20 x

to the left side

4 x^{2} + 17 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 20 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 17}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 17 = 82

x_{1, 2} = \frac{- ( - 20 ) \pm 8 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8 2}{2 \cdot 4}, x_{2} = \frac{- ( - 20 ) - 8 2}{2 \cdot 4}

x = \frac{- ( - 20 ) + 8 2}{2 \cdot 4} : \frac{5 + 2 2}{2}

x = \frac{- ( - 20 ) - 8 2}{2 \cdot 4} : \frac{5 - 2 2}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 2 2}{2}, x = \frac{5 - 2 2}{2}

4 t^{2} - 19 t - 30 = 0

1 - 2 x^{2} - x = 0

5 t^{2} + 15 t + 7 = 0

9 d^{2} = 1

100 x^{2} - 10011 x - 10.11 = 0

What are the solutions to the equation 4x^2+17=20x ?
The solutions to the equation 4x^2+17=20x are x=(5+2sqrt(2))/2 ,x=(5-2sqrt(2))/2
Find the zeros of 4x^2+17=20x
The zeros of 4x^2+17=20x are x=(5+2sqrt(2))/2 ,x=(5-2sqrt(2))/2