What is factor x^2+3x+9/4 ?

The solution to factor x^2+3x+9/4 is (x+3/2)^2

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factor x^2+3x+9/4

factor

x^{2} + 3 x + \frac{9}{4}

(x + \frac{3}{2})^{2}

Solution steps

x^{2} + 3 x + \frac{9}{4}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

\frac{9}{4} = (\frac{3}{2})^{2}

3 x = 2 x \frac{3}{2}

= x^{2} + 2 x \frac{3}{2} + (\frac{3}{2})^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

x^{2} + 2 x \frac{3}{2} + (\frac{3}{2})^{2} = (x + \frac{3}{2})^{2}

= (x + \frac{3}{2})^{2}

\frac{2 π}{\frac{1}{8}}

\frac{6 x ^{2} y ^{3}}{( - 4 x ^{4} y ) ( - 3 x ^{3} y ^{2} )}

\frac{2 x - 3}{4} + 6 \geq 2 + \frac{4 x}{3}

t^{2} - 5 t + 4

4 x^{2} = 16