What is (2x-3)/4+6>= 2+(4x)/3 ?

The solution to (2x-3)/4+6>= 2+(4x)/3 is x<= 39/10

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(2x-3)/4+6>= 2+(4x)/3

\frac{2 x - 3}{4} + 6 \geq 2 + \frac{4 x}{3}

x \leq \frac{39}{10}

Interval Notation

(- \infty, \frac{39}{10}]

Decimal Notation

x \leq 3.9

Solution steps

\frac{2 x - 3}{4} + 6 \geq 2 + \frac{4 x}{3}

Multiply by LCM

3 (2 x - 3) + 72 \geq 24 + 16 x

Expand

3 (2 x - 3) + 72 : 6 x + 63

6 x + 63 \geq 24 + 16 x

Move

63

to the right side

6 x \geq 16 x - 39

Move

16 x

to the left side

- 10 x \geq - 39

Multiply both sides by

- 1

10 x \leq 39

Divide both sides by

10

x \leq \frac{39}{10}

t^{2} - 5 t + 4

4 x^{2} = 16

4^{5}

\frac{6 !}{( 6 - 5 ) ! 5 !}

625 (0.15625) + 25 (- 7.1875) + c = 25

What is (2x-3)/4+6>= 2+(4x)/3 ?
The solution to (2x-3)/4+6>= 2+(4x)/3 is x<= 39/10