What are the solutions to the equation a=2pir^2+2pi ?

The solutions to the equation a=2pir^2+2pi are r=sqrt((a-2pi)/(2pi)),r=-sqrt((a-2pi)/(2pi))

Find the zeros of a=2pir^2+2pi

The zeros of a=2pir^2+2pi are r=sqrt((a-2pi)/(2pi)),r=-sqrt((a-2pi)/(2pi))

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a = 2 π r^{2} + 2 π

r = \frac{a - 2 π}{2 π}, r = - \frac{a - 2 π}{2 π}

Solution steps

a = 2 π r^{2} + 2 π

Switch sides

2 π r^{2} + 2 π = a

Move

2 π

to the right side

2 π r^{2} = a - 2 π

Divide both sides by

2 π

r^{2} = \frac{a - 2 π}{2 π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{a - 2 π}{2 π}, r = - \frac{a - 2 π}{2 π}

x^{2} + 2 x - 575 = 0

3 x^{2} + 17 = - 10 x + 9

x^{2} + 6 x - 100 = 6 x

120 = x + \frac{x ^{2}}{20}

d^{2} - 9 d + 11 = 0

What are the solutions to the equation a=2pir^2+2pi ?
The solutions to the equation a=2pir^2+2pi are r=sqrt((a-2pi)/(2pi)),r=-sqrt((a-2pi)/(2pi))
Find the zeros of a=2pir^2+2pi
The zeros of a=2pir^2+2pi are r=sqrt((a-2pi)/(2pi)),r=-sqrt((a-2pi)/(2pi))