What are the solutions to the equation -x^2=-4x ?

The solutions to the equation -x^2=-4x are x=0,x=4

Find the zeros of -x^2=-4x

The zeros of -x^2=-4x are x=0,x=4

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- x^{2} = - 4 x

x = 0, x = 4

Solution steps

- x^{2} = - 4 x

Move

4 x

to the left side

- x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

4^{2} - 4 (- 1) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 1 )}, x_{2} = \frac{- 4 - 4}{2 ( - 1 )}

x = \frac{- 4 + 4}{2 ( - 1 )} : 0

x = \frac{- 4 - 4}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

(4 + x)^{2} - (2 x - 1)^{2} = - 12 (5 - x)

2 (x + 1) = x^{2}

- 16 t^{2} + 184 t + 96 = 0

2 x^{2} - 2 x - 24 = 0

4 x^{2} - 28 x + 49 = 0

What are the solutions to the equation -x^2=-4x ?
The solutions to the equation -x^2=-4x are x=0,x=4
Find the zeros of -x^2=-4x
The zeros of -x^2=-4x are x=0,x=4