What are the solutions to the equation -16t^2+184t+96=0 ?

The solutions to the equation -16t^2+184t+96=0 are t=-1/2 ,t=12

Find the zeros of -16t^2+184t+96=0

The zeros of -16t^2+184t+96=0 are t=-1/2 ,t=12

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- 16 t^{2} + 184 t + 96 = 0

t = - \frac{1}{2}, t = 12

Decimal Notation

t = - 0.5, t = 12

Solution steps

- 16 t^{2} + 184 t + 96 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 184 \pm 18 4 ^{2} - 4 ( - 16 ) \cdot 96}{2 ( - 16 )}

18 4^{2} - 4 (- 16) \cdot 96 = 200

t_{1, 2} = \frac{- 184 \pm 200}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 184 + 200}{2 ( - 16 )}, t_{2} = \frac{- 184 - 200}{2 ( - 16 )}

t = \frac{- 184 + 200}{2 ( - 16 )} : - \frac{1}{2}

t = \frac{- 184 - 200}{2 ( - 16 )} : 12

The solutions to the quadratic equation are:

t = - \frac{1}{2}, t = 12

2 x^{2} - 2 x - 24 = 0

4 x^{2} - 28 x + 49 = 0

x^{2} - 42 x - 88 = 0

y^{2} + 5 y = 24

16 (4 + 2 x)^{2} - 47 = 2

What are the solutions to the equation -16t^2+184t+96=0 ?
The solutions to the equation -16t^2+184t+96=0 are t=-1/2 ,t=12
Find the zeros of -16t^2+184t+96=0
The zeros of -16t^2+184t+96=0 are t=-1/2 ,t=12