What are the solutions to the equation d^2+9d+12=-4 ?

The solutions to the equation d^2+9d+12=-4 are d=(-9+sqrt(17))/2 ,d=(-9-sqrt(17))/2

Find the zeros of d^2+9d+12=-4

The zeros of d^2+9d+12=-4 are d=(-9+sqrt(17))/2 ,d=(-9-sqrt(17))/2

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d^{2} + 9 d + 12 = - 4

d = \frac{- 9 + 17}{2}, d = \frac{- 9 - 17}{2}

Decimal Notation

d = - 2.43844 \dots, d = - 6.56155 \dots

Solution steps

d^{2} + 9 d + 12 = - 4

Move

4

to the left side

d^{2} + 9 d + 16 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 16 = 17

d_{1, 2} = \frac{- 9 \pm 17}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- 9 + 17}{2 \cdot 1}, d_{2} = \frac{- 9 - 17}{2 \cdot 1}

d = \frac{- 9 + 17}{2 \cdot 1} : \frac{- 9 + 17}{2}

d = \frac{- 9 - 17}{2 \cdot 1} : \frac{- 9 - 17}{2}

The solutions to the quadratic equation are:

d = \frac{- 9 + 17}{2}, d = \frac{- 9 - 17}{2}

y^{2} - 15 y - 54 = 0

(- 3) 1 0^{- 6} x^{2} + 0.003 x + 6 = 0

4 x^{2} + 72 x + 388 = 0

- 2 x^{2} = 32

x^{2} - 2 x + 20

What are the solutions to the equation d^2+9d+12=-4 ?
The solutions to the equation d^2+9d+12=-4 are d=(-9+sqrt(17))/2 ,d=(-9-sqrt(17))/2
Find the zeros of d^2+9d+12=-4
The zeros of d^2+9d+12=-4 are d=(-9+sqrt(17))/2 ,d=(-9-sqrt(17))/2