What are the solutions to the equation -2x^2=32 ?

The solutions to the equation -2x^2=32 are x=4i,x=-4i

Find the zeros of -2x^2=32

The zeros of -2x^2=32 are x=4i,x=-4i

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- 2 x^{2} = 32

x = 4 i, x = - 4 i

Solution steps

- 2 x^{2} = 32

Divide both sides by

- 2

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

x^{2} - 2 x + 20

25 x^{2} - 30 x + 9 = 96

4 x^{2} - 60 = 0

x^{2} - 3 x + 4

x^{2} - 3 x - 2

What are the solutions to the equation -2x^2=32 ?
The solutions to the equation -2x^2=32 are x=4i,x=-4i
Find the zeros of -2x^2=32
The zeros of -2x^2=32 are x=4i,x=-4i