What are the solutions to the equation (-3)10^{-6}x^2+0.003x+6=0 ?

The solutions to the equation (-3)10^{-6}x^2+0.003x+6=0 are x=-1000,x=2000

Find the zeros of (-3)10^{-6}x^2+0.003x+6=0

The zeros of (-3)10^{-6}x^2+0.003x+6=0 are x=-1000,x=2000

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(- 3) 1 0^{- 6} x^{2} + 0.003 x + 6 = 0

x = - 1000, x = 2000

Solution steps

(- 3) \cdot 1 0^{- 6} x^{2} + 0.003 x + 6 = 0

Multiply both sides by

1000

- \frac{3}{1000} x^{2} + 3 x + 6000 = 0

Multiply both sides by

1000

- 3 x^{2} + 3000 x + 6000000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3000 \pm 300 0 ^{2} - 4 ( - 3 ) \cdot 6000000}{2 ( - 3 )}

300 0^{2} - 4 (- 3) \cdot 6000000 = 9000

x_{1, 2} = \frac{- 3000 \pm 9000}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3000 + 9000}{2 ( - 3 )}, x_{2} = \frac{- 3000 - 9000}{2 ( - 3 )}

x = \frac{- 3000 + 9000}{2 ( - 3 )} : - 1000

x = \frac{- 3000 - 9000}{2 ( - 3 )} : 2000

The solutions to the quadratic equation are:

x = - 1000, x = 2000

4 x^{2} + 72 x + 388 = 0

- 2 x^{2} = 32

x^{2} - 2 x + 20

25 x^{2} - 30 x + 9 = 96

4 x^{2} - 60 = 0

What are the solutions to the equation (-3)10^{-6}x^2+0.003x+6=0 ?
The solutions to the equation (-3)10^{-6}x^2+0.003x+6=0 are x=-1000,x=2000
Find the zeros of (-3)10^{-6}x^2+0.003x+6=0
The zeros of (-3)10^{-6}x^2+0.003x+6=0 are x=-1000,x=2000