What are the solutions to the equation roots x^2-2x-6 ?

The solutions to the equation roots x^2-2x-6 are x=1+sqrt(7),x=1-sqrt(7)

Find the zeros of roots x^2-2x-6

The zeros of roots x^2-2x-6 are x=1+sqrt(7),x=1-sqrt(7)

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roots

x^{2} - 2 x - 6

x = 1 + 7, x = 1 - 7

Solution steps

x^{2} - 2 x - 6

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 6) = 27

x_{1, 2} = \frac{- ( - 2 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 7}{2 \cdot 1} : 1 + 7

x = \frac{- ( - 2 ) - 2 7}{2 \cdot 1} : 1 - 7

The solutions to the quadratic equation are:

x = 1 + 7, x = 1 - 7

12 x^{2} - 26 x - 7 = 3 x + 1

3 x^{2} + 20 x + 16 = 6 x^{2} + 32 x + 28

(x + 5)^{2} = (5 - x)^{2} + (5 - x)^{2}

(- x + 2) (4 x + 4) = 0

a^{2} - 49 = 0

What are the solutions to the equation roots x^2-2x-6 ?
The solutions to the equation roots x^2-2x-6 are x=1+sqrt(7),x=1-sqrt(7)
Find the zeros of roots x^2-2x-6
The zeros of roots x^2-2x-6 are x=1+sqrt(7),x=1-sqrt(7)