What are the solutions to the equation -2x^2+x+9=0 ?

The solutions to the equation -2x^2+x+9=0 are x=-(-1+sqrt(73))/4 ,x=(1+sqrt(73))/4

Find the zeros of -2x^2+x+9=0

The zeros of -2x^2+x+9=0 are x=-(-1+sqrt(73))/4 ,x=(1+sqrt(73))/4

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- 2 x^{2} + x + 9 = 0

x = - \frac{- 1 + 73}{4}, x = \frac{1 + 73}{4}

Decimal Notation

x = - 1.88600 \dots, x = 2.38600 \dots

Solution steps

- 2 x^{2} + x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 9}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 9 = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 ( - 2 )}, x_{2} = \frac{- 1 - 73}{2 ( - 2 )}

x = \frac{- 1 + 73}{2 ( - 2 )} : - \frac{- 1 + 73}{4}

x = \frac{- 1 - 73}{2 ( - 2 )} : \frac{1 + 73}{4}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 73}{4}, x = \frac{1 + 73}{4}

2 x^{2} + 4 x + 11 = 0

a, n = 4 a^{2} - m

x^{2} - 5 x - 6

3 x^{2} - 31 x + 60 = 0

y, 3 x^{2} - 3 + 3 y^{2} = 6 x y

What are the solutions to the equation -2x^2+x+9=0 ?
The solutions to the equation -2x^2+x+9=0 are x=-(-1+sqrt(73))/4 ,x=(1+sqrt(73))/4
Find the zeros of -2x^2+x+9=0
The zeros of -2x^2+x+9=0 are x=-(-1+sqrt(73))/4 ,x=(1+sqrt(73))/4