What are the solutions to the equation 16(5-2x)^2+33=42 ?

The solutions to the equation 16(5-2x)^2+33=42 are x= 17/8 ,x= 23/8

Find the zeros of 16(5-2x)^2+33=42

The zeros of 16(5-2x)^2+33=42 are x= 17/8 ,x= 23/8

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16 (5 - 2 x)^{2} + 33 = 42

x = \frac{17}{8}, x = \frac{23}{8}

Decimal Notation

x = 2.125, x = 2.875

Solution steps

16 (5 - 2 x)^{2} + 33 = 42

Move

33

to the right side

16 (5 - 2 x)^{2} = 9

Divide both sides by

16

(5 - 2 x)^{2} = \frac{9}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 - 2 x = \frac{9}{16} : x = \frac{17}{8}

Solve

5 - 2 x = - \frac{9}{16} : x = \frac{23}{8}

The solutions to the quadratic equation are:

x = \frac{17}{8}, x = \frac{23}{8}

- s^{2} - 2 s + 5 = 0

y, 40 x^{2} + 3 y^{2} - 7 x + y + 1 = 0

t^{2} + 6 t - 4 = 0

x^{2} + 6 x + 19 = 4 x

10 x^{2} = 80 x

What are the solutions to the equation 16(5-2x)^2+33=42 ?
The solutions to the equation 16(5-2x)^2+33=42 are x= 17/8 ,x= 23/8
Find the zeros of 16(5-2x)^2+33=42
The zeros of 16(5-2x)^2+33=42 are x= 17/8 ,x= 23/8