What are the solutions to the equation ax^2+2x+1=0 ?

The solutions to the equation ax^2+2x+1=0 are x=(-1+sqrt(-a+1))/a ,x=-(sqrt(-a+1)+1)/a ;\quad a\ne 0

Find the zeros of ax^2+2x+1=0

The zeros of ax^2+2x+1=0 are x=(-1+sqrt(-a+1))/a ,x=-(sqrt(-a+1)+1)/a ;\quad a\ne 0

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a x^{2} + 2 x + 1 = 0

x = \frac{- 1 + - a + 1}{a}, x = - \frac{- a + 1 + 1}{a}; a \neq = 0

Solution steps

a x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 a \cdot 1}{2 a}

Simplify

2^{2} - 4 a \cdot 1 : 2 1 - a

x_{1, 2} = \frac{- 2 \pm 2 1 - a}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- 2 + 2 1 - a}{2 a}, x_{2} = \frac{- 2 - 2 1 - a}{2 a}

x = \frac{- 2 + 2 1 - a}{2 a} : \frac{- 1 + - a + 1}{a}

x = \frac{- 2 - 2 1 - a}{2 a} : - \frac{- a + 1 + 1}{a}

The solutions to the quadratic equation are:

x = \frac{- 1 + - a + 1}{a}, x = - \frac{- a + 1 + 1}{a}; a \neq = 0

2 x^{2} + 3 x - 1

25 x^{2} - 10 x = - 1

x, y = 2 x^{2} - 12 x - 11

96 x^{2} + 660 x - 84 = 0

x^{2} - 4 x + 8 = 3

What are the solutions to the equation ax^2+2x+1=0 ?
The solutions to the equation ax^2+2x+1=0 are x=(-1+sqrt(-a+1))/a ,x=-(sqrt(-a+1)+1)/a ;\quad a\ne 0
Find the zeros of ax^2+2x+1=0
The zeros of ax^2+2x+1=0 are x=(-1+sqrt(-a+1))/a ,x=-(sqrt(-a+1)+1)/a ;\quad a\ne 0