What are the solutions to the equation roots x^2+9x+c ?

The solutions to the equation roots x^2+9x+c are x=(-9+sqrt(81-4c))/2 ,x=(-9-sqrt(81-4c))/2

Find the zeros of roots x^2+9x+c

The zeros of roots x^2+9x+c are x=(-9+sqrt(81-4c))/2 ,x=(-9-sqrt(81-4c))/2

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roots

x^{2} + 9 x + c

x = \frac{- 9 + 81 - 4 c}{2}, x = \frac{- 9 - 81 - 4 c}{2}

Solution steps

x^{2} + 9 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 9 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

9^{2} - 4 \cdot 1 \cdot c : 81 - 4 c

x_{1, 2} = \frac{- 9 \pm 81 - 4 c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 81 - 4 c}{2 \cdot 1}, x_{2} = \frac{- 9 - 81 - 4 c}{2 \cdot 1}

x = \frac{- 9 + 81 - 4 c}{2 \cdot 1} : \frac{- 9 + 81 - 4 c}{2}

x = \frac{- 9 - 81 - 4 c}{2 \cdot 1} : \frac{- 9 - 81 - 4 c}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 81 - 4 c}{2}, x = \frac{- 9 - 81 - 4 c}{2}

x^{2} + 12 x + 27 = 0

2 + x = 6 x^{2}

13 x^{2} + 78 x = 0

x, x^{2} + 18 x + 81 = 25

(x - 1)^{2} - 25

What are the solutions to the equation roots x^2+9x+c ?
The solutions to the equation roots x^2+9x+c are x=(-9+sqrt(81-4c))/2 ,x=(-9-sqrt(81-4c))/2
Find the zeros of roots x^2+9x+c
The zeros of roots x^2+9x+c are x=(-9+sqrt(81-4c))/2 ,x=(-9-sqrt(81-4c))/2