What are the solutions to the equation 3m^2-4m-4=m ?

The solutions to the equation 3m^2-4m-4=m are m=(5+sqrt(73))/6 ,m=(5-sqrt(73))/6

Find the zeros of 3m^2-4m-4=m

The zeros of 3m^2-4m-4=m are m=(5+sqrt(73))/6 ,m=(5-sqrt(73))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 m^{2} - 4 m - 4 = m

m = \frac{5 + 73}{6}, m = \frac{5 - 73}{6}

Decimal Notation

m = 2.25733 \dots, m = - 0.59066 \dots

Solution steps

3 m^{2} - 4 m - 4 = m

Move

m

to the left side

3 m^{2} - 5 m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 4) = 73

m_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 3}, m_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 3}

m = \frac{- ( - 5 ) + 73}{2 \cdot 3} : \frac{5 + 73}{6}

m = \frac{- ( - 5 ) - 73}{2 \cdot 3} : \frac{5 - 73}{6}

The solutions to the quadratic equation are:

m = \frac{5 + 73}{6}, m = \frac{5 - 73}{6}

4 x^{2} - 12 x + 9 = 36

- 5 v^{2} + 9 v + 1 = - 6 v^{2}

3 x^{2} + 28 x + 49 = 0

d^{2} + 10 d + 28 = 3

x^{2} + 61 = 1 - 17 x

What are the solutions to the equation 3m^2-4m-4=m ?
The solutions to the equation 3m^2-4m-4=m are m=(5+sqrt(73))/6 ,m=(5-sqrt(73))/6
Find the zeros of 3m^2-4m-4=m
The zeros of 3m^2-4m-4=m are m=(5+sqrt(73))/6 ,m=(5-sqrt(73))/6