What are the solutions to the equation 3(x-2)^2=27 ?

The solutions to the equation 3(x-2)^2=27 are x=5,x=-1

Find the zeros of 3(x-2)^2=27

The zeros of 3(x-2)^2=27 are x=5,x=-1

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3 (x - 2)^{2} = 27

x = 5, x = - 1

Solution steps

3 (x - 2)^{2} = 27

Divide both sides by

3

(x - 2)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 9 : x = 5

Solve

x - 2 = - 9 : x = - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

5 x^{2} = - x + 7

2 k^{2} + 3 k - 1 = 0

y, - 5 x^{2} + 60 x + 7 y^{2} + 84 y + 72 = 0

(x - 3)^{2} + 6 = 26

5 x^{2} - 3 x - 15 = 0

What are the solutions to the equation 3(x-2)^2=27 ?
The solutions to the equation 3(x-2)^2=27 are x=5,x=-1
Find the zeros of 3(x-2)^2=27
The zeros of 3(x-2)^2=27 are x=5,x=-1