What are the solutions to the equation (x-3)^2+6=26 ?

The solutions to the equation (x-3)^2+6=26 are x=2sqrt(5)+3,x=-2sqrt(5)+3

Find the zeros of (x-3)^2+6=26

The zeros of (x-3)^2+6=26 are x=2sqrt(5)+3,x=-2sqrt(5)+3

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(x - 3)^{2} + 6 = 26

x = 25 + 3, x = - 25 + 3

Decimal Notation

x = 7.47213 \dots, x = - 1.47213 \dots

Solution steps

(x - 3)^{2} + 6 = 26

Move

6

to the right side

(x - 3)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 20 : x = 25 + 3

Solve

x - 3 = - 20 : x = - 25 + 3

The solutions to the quadratic equation are:

x = 25 + 3, x = - 25 + 3

5 x^{2} - 3 x - 15 = 0

5 x^{2} - 40 x + 75 = 0

a^{2} + x^{2}

x, x^{2} + y^{2} + z^{2} = 2 z

m^{2} - 10 m + 26 = 0

What are the solutions to the equation (x-3)^2+6=26 ?
The solutions to the equation (x-3)^2+6=26 are x=2sqrt(5)+3,x=-2sqrt(5)+3
Find the zeros of (x-3)^2+6=26
The zeros of (x-3)^2+6=26 are x=2sqrt(5)+3,x=-2sqrt(5)+3