What are the solutions to the equation m^2-10m+26=0 ?

The solutions to the equation m^2-10m+26=0 are m=5+i,m=5-i

Find the zeros of m^2-10m+26=0

The zeros of m^2-10m+26=0 are m=5+i,m=5-i

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m^{2} - 10 m + 26 = 0

m = 5 + i, m = 5 - i

Solution steps

m^{2} - 10 m + 26 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 26 : 2 i

m_{1, 2} = \frac{- ( - 10 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 10 ) + 2 i}{2 \cdot 1}, m_{2} = \frac{- ( - 10 ) - 2 i}{2 \cdot 1}

m = \frac{- ( - 10 ) + 2 i}{2 \cdot 1} : 5 + i

m = \frac{- ( - 10 ) - 2 i}{2 \cdot 1} : 5 - i

The solutions to the quadratic equation are:

m = 5 + i, m = 5 - i

1 - 0.5 x - 0.4 x^{2} = 0

4 = - 8 x^{2} + 8 x + 10

x^{2} + 10 x = - 1

a^{2} + 2 ab + b^{2} - x^{2}

3.02 x^{2} + 16 x - 7.02 = 0

What are the solutions to the equation m^2-10m+26=0 ?
The solutions to the equation m^2-10m+26=0 are m=5+i,m=5-i
Find the zeros of m^2-10m+26=0
The zeros of m^2-10m+26=0 are m=5+i,m=5-i