What are the solutions to the equation 4=-8x^2+8x+10 ?

The solutions to the equation 4=-8x^2+8x+10 are x=-1/2 ,x= 3/2

Find the zeros of 4=-8x^2+8x+10

The zeros of 4=-8x^2+8x+10 are x=-1/2 ,x= 3/2

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4 = - 8 x^{2} + 8 x + 10

x = - \frac{1}{2}, x = \frac{3}{2}

Decimal Notation

x = - 0.5, x = 1.5

Solution steps

4 = - 8 x^{2} + 8 x + 10

Switch sides

- 8 x^{2} + 8 x + 10 = 4

Move

4

to the left side

- 8 x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 8 ) \cdot 6}{2 ( - 8 )}

8^{2} - 4 (- 8) \cdot 6 = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 ( - 8 )}, x_{2} = \frac{- 8 - 16}{2 ( - 8 )}

x = \frac{- 8 + 16}{2 ( - 8 )} : - \frac{1}{2}

x = \frac{- 8 - 16}{2 ( - 8 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = \frac{3}{2}

x^{2} + 10 x = - 1

a^{2} + 2 ab + b^{2} - x^{2}

3.02 x^{2} + 16 x - 7.02 = 0

x^{2} + x - 12 = x + 4

16 x^{2} = 81

What are the solutions to the equation 4=-8x^2+8x+10 ?
The solutions to the equation 4=-8x^2+8x+10 are x=-1/2 ,x= 3/2
Find the zeros of 4=-8x^2+8x+10
The zeros of 4=-8x^2+8x+10 are x=-1/2 ,x= 3/2