What are the solutions to the equation roots s^2+2s+3 ?

The solutions to the equation roots s^2+2s+3 are s=-1+sqrt(2)i,s=-1-sqrt(2)i

Find the zeros of roots s^2+2s+3

The zeros of roots s^2+2s+3 are s=-1+sqrt(2)i,s=-1-sqrt(2)i

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roots

s^{2} + 2 s + 3

s = - 1 + 2 i, s = - 1 - 2 i

Solution steps

s^{2} + 2 s + 3

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 2 s + 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

s_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

s = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

s = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

s = - 1 + 2 i, s = - 1 - 2 i

4 r^{2} - 8 r = 96

x^{2} + a x + b

x, - x^{2} + y^{2} - z^{2} = 1

17 x^{2} + 8 x = 0

2 x^{2} - x - 18 = 0

What are the solutions to the equation roots s^2+2s+3 ?
The solutions to the equation roots s^2+2s+3 are s=-1+sqrt(2)i,s=-1-sqrt(2)i
Find the zeros of roots s^2+2s+3
The zeros of roots s^2+2s+3 are s=-1+sqrt(2)i,s=-1-sqrt(2)i