What are the solutions to the equation 11x^2=7-2x ?

The solutions to the equation 11x^2=7-2x are x=(-1+sqrt(78))/(11),x=-(1+sqrt(78))/(11)

Find the zeros of 11x^2=7-2x

The zeros of 11x^2=7-2x are x=(-1+sqrt(78))/(11),x=-(1+sqrt(78))/(11)

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11 x^{2} = 7 - 2 x

x = \frac{- 1 + 78}{11}, x = - \frac{1 + 78}{11}

Decimal Notation

x = 0.71197 \dots, x = - 0.89379 \dots

Solution steps

11 x^{2} = 7 - 2 x

Move

2 x

to the left side

11 x^{2} + 2 x = 7

Move

7

to the left side

11 x^{2} + 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 11 ( - 7 )}{2 \cdot 11}

2^{2} - 4 \cdot 11 (- 7) = 278

x_{1, 2} = \frac{- 2 \pm 2 78}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 2 + 2 78}{2 \cdot 11}, x_{2} = \frac{- 2 - 2 78}{2 \cdot 11}

x = \frac{- 2 + 2 78}{2 \cdot 11} : \frac{- 1 + 78}{11}

x = \frac{- 2 - 2 78}{2 \cdot 11} : - \frac{1 + 78}{11}

The solutions to the quadratic equation are:

x = \frac{- 1 + 78}{11}, x = - \frac{1 + 78}{11}

x^{2} + 6 x + 6 = 0

x^{2} + 22 x = 45

6 x^{2} = 11 x

2 t^{2} + 2 t - 1 = 0

x^{2} + 3 x + 1

What are the solutions to the equation 11x^2=7-2x ?
The solutions to the equation 11x^2=7-2x are x=(-1+sqrt(78))/(11),x=-(1+sqrt(78))/(11)
Find the zeros of 11x^2=7-2x
The zeros of 11x^2=7-2x are x=(-1+sqrt(78))/(11),x=-(1+sqrt(78))/(11)