What are the solutions to the equation x^2+22x=45 ?

The solutions to the equation x^2+22x=45 are x=-11+sqrt(166),x=-11-sqrt(166)

Find the zeros of x^2+22x=45

The zeros of x^2+22x=45 are x=-11+sqrt(166),x=-11-sqrt(166)

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x^{2} + 22 x = 45

x = - 11 + 166, x = - 11 - 166

Decimal Notation

x = 1.88409 \dots, x = - 23.88409 \dots

Solution steps

x^{2} + 22 x = 45

Move

45

to the left side

x^{2} + 22 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot ( - 45 )}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot (- 45) = 2166

x_{1, 2} = \frac{- 22 \pm 2 166}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 2 166}{2 \cdot 1}, x_{2} = \frac{- 22 - 2 166}{2 \cdot 1}

x = \frac{- 22 + 2 166}{2 \cdot 1} : - 11 + 166

x = \frac{- 22 - 2 166}{2 \cdot 1} : - 11 - 166

The solutions to the quadratic equation are:

x = - 11 + 166, x = - 11 - 166

6 x^{2} = 11 x

2 t^{2} + 2 t - 1 = 0

x^{2} + 3 x + 1

4 X^{2} + 5 X - 51 = 0

4 x^{2} - 20 x = - 45

What are the solutions to the equation x^2+22x=45 ?
The solutions to the equation x^2+22x=45 are x=-11+sqrt(166),x=-11-sqrt(166)
Find the zeros of x^2+22x=45
The zeros of x^2+22x=45 are x=-11+sqrt(166),x=-11-sqrt(166)