What are the solutions to the equation 4X^2+5X-51=0 ?

The solutions to the equation 4X^2+5X-51=0 are X=3,X=-17/4

Find the zeros of 4X^2+5X-51=0

The zeros of 4X^2+5X-51=0 are X=3,X=-17/4

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4 X^{2} + 5 X - 51 = 0

X = 3, X = - \frac{17}{4}

Decimal Notation

X = 3, X = - 4.25

Solution steps

4 X^{2} + 5 X - 51 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 51 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 51) = 29

X_{1, 2} = \frac{- 5 \pm 29}{2 \cdot 4}

Separate the solutions

X_{1} = \frac{- 5 + 29}{2 \cdot 4}, X_{2} = \frac{- 5 - 29}{2 \cdot 4}

X = \frac{- 5 + 29}{2 \cdot 4} : 3

X = \frac{- 5 - 29}{2 \cdot 4} : - \frac{17}{4}

The solutions to the quadratic equation are:

X = 3, X = - \frac{17}{4}

4 x^{2} - 20 x = - 45

y, x^{2} y^{3} = 1

x^{2} + 5 x - 6 = 0

(3 v - 2) (2 v + 1) = 3 v^{2} - 11 v - 10

5 x^{2} - 50 x + 125 = 0

What are the solutions to the equation 4X^2+5X-51=0 ?
The solutions to the equation 4X^2+5X-51=0 are X=3,X=-17/4
Find the zeros of 4X^2+5X-51=0
The zeros of 4X^2+5X-51=0 are X=3,X=-17/4