What are the solutions to the equation 19+2x^2=21 ?

The solutions to the equation 19+2x^2=21 are x=1,x=-1

Find the zeros of 19+2x^2=21

The zeros of 19+2x^2=21 are x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

19 + 2 x^{2} = 21

x = 1, x = - 1

Solution steps

19 + 2 x^{2} = 21

Move

19

to the right side

2 x^{2} = 2

Divide both sides by

2

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

x, x^{2} + 4 x + 10 = 0

lo g_{10} (3) x^{2} - lo g_{10} (3) = 2

x^{2} - 2 x + 2 = 2 - x^{2}

x, (x - a)^{2} + y^{2} = d^{2}

3 x^{2} + (m + 2) x - 5 + m = 0

What are the solutions to the equation 19+2x^2=21 ?
The solutions to the equation 19+2x^2=21 are x=1,x=-1
Find the zeros of 19+2x^2=21
The zeros of 19+2x^2=21 are x=1,x=-1