What are the solutions to the equation (x+2)^2+10=26 ?

The solutions to the equation (x+2)^2+10=26 are x=2,x=-6

Find the zeros of (x+2)^2+10=26

The zeros of (x+2)^2+10=26 are x=2,x=-6

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(x + 2)^{2} + 10 = 26

x = 2, x = - 6

Solution steps

(x + 2)^{2} + 10 = 26

Move

10

to the right side

(x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

(m - 2)^{2} + 3 = 28

5 x^{2} + 11 x + 2 = 0

39 = - (\frac{x ^{2}}{200}) + x - 2

x^{2} - \frac{15}{81} = \frac{539}{891}

5 n^{2} + 1 = 0

What are the solutions to the equation (x+2)^2+10=26 ?
The solutions to the equation (x+2)^2+10=26 are x=2,x=-6
Find the zeros of (x+2)^2+10=26
The zeros of (x+2)^2+10=26 are x=2,x=-6