What are the solutions to the equation 2p^2-p=91 ?

The solutions to the equation 2p^2-p=91 are p=7,p=-13/2

Find the zeros of 2p^2-p=91

The zeros of 2p^2-p=91 are p=7,p=-13/2

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2 p^{2} - p = 91

p = 7, p = - \frac{13}{2}

Decimal Notation

p = 7, p = - 6.5

Solution steps

2 p^{2} - p = 91

Move

91

to the left side

2 p^{2} - p - 91 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 91 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 91) = 27

p_{1, 2} = \frac{- ( - 1 ) \pm 27}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- ( - 1 ) + 27}{2 \cdot 2}, p_{2} = \frac{- ( - 1 ) - 27}{2 \cdot 2}

p = \frac{- ( - 1 ) + 27}{2 \cdot 2} : 7

p = \frac{- ( - 1 ) - 27}{2 \cdot 2} : - \frac{13}{2}

The solutions to the quadratic equation are:

p = 7, p = - \frac{13}{2}

x^{2} + \frac{5}{2} x - 5 = 0

x, 2 x - x^{2} = 0.5

3 x^{2} - 9 a x^{2} - x + 3 a

(x - 3)^{2} + (x + 4)^{2} = 29

x^{2} y^{2} + x y = 6, y

What are the solutions to the equation 2p^2-p=91 ?
The solutions to the equation 2p^2-p=91 are p=7,p=-13/2
Find the zeros of 2p^2-p=91
The zeros of 2p^2-p=91 are p=7,p=-13/2