What are the solutions to the equation solvefor x^2y^2+xy=6,y ?

The solutions to the equation solvefor x^2y^2+xy=6,y are y= 2/x ,y=-3/x ;\quad x\ne 0

Find the zeros of solvefor x^2y^2+xy=6,y

The zeros of solvefor x^2y^2+xy=6,y are y= 2/x ,y=-3/x ;\quad x\ne 0

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solve for

x^{2} y^{2} + x y = 6, y

y = \frac{2}{x}, y = - \frac{3}{x}; x \neq = 0

Solution steps

x^{2} y^{2} + x y = 6

Move

6

to the left side

x^{2} y^{2} + x y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- x \pm x ^{2} - 4 x ^{2} ( - 6 )}{2 x ^{2}}

Simplify

x^{2} - 4 x^{2} (- 6) : 5 x

y_{1, 2} = \frac{- x \pm 5 x}{2 x ^{2}}; x \neq = 0

Separate the solutions

y_{1} = \frac{- x + 5 x}{2 x ^{2}}, y_{2} = \frac{- x - 5 x}{2 x ^{2}}

y = \frac{- x + 5 x}{2 x ^{2}} : \frac{2}{x}

y = \frac{- x - 5 x}{2 x ^{2}} : - \frac{3}{x}

The solutions to the quadratic equation are:

y = \frac{2}{x}, y = - \frac{3}{x}; x \neq = 0

a^{2} + n^{2}

2 x^{2} - 5 = 27

4 x^{2} - 16 x = 9

5 x^{2} - 8 x + 12 = 0

x^{2} + 3 x - 3 = 7 x + 9

What are the solutions to the equation solvefor x^2y^2+xy=6,y ?
The solutions to the equation solvefor x^2y^2+xy=6,y are y= 2/x ,y=-3/x ;\quad x\ne 0
Find the zeros of solvefor x^2y^2+xy=6,y
The zeros of solvefor x^2y^2+xy=6,y are y= 2/x ,y=-3/x ;\quad x\ne 0