What are the solutions to the equation -m^2-7m-4=-2m^2 ?

The solutions to the equation -m^2-7m-4=-2m^2 are m=(7+sqrt(65))/2 ,m=(7-sqrt(65))/2

Find the zeros of -m^2-7m-4=-2m^2

The zeros of -m^2-7m-4=-2m^2 are m=(7+sqrt(65))/2 ,m=(7-sqrt(65))/2

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- m^{2} - 7 m - 4 = - 2 m^{2}

m = \frac{7 + 65}{2}, m = \frac{7 - 65}{2}

Decimal Notation

m = 7.53112 \dots, m = - 0.53112 \dots

Solution steps

- m^{2} - 7 m - 4 = - 2 m^{2}

Move

2 m^{2}

to the left side

m^{2} - 7 m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 4) = 65

m_{1, 2} = \frac{- ( - 7 ) \pm 65}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 7 ) + 65}{2 \cdot 1}, m_{2} = \frac{- ( - 7 ) - 65}{2 \cdot 1}

m = \frac{- ( - 7 ) + 65}{2 \cdot 1} : \frac{7 + 65}{2}

m = \frac{- ( - 7 ) - 65}{2 \cdot 1} : \frac{7 - 65}{2}

The solutions to the quadratic equation are:

m = \frac{7 + 65}{2}, m = \frac{7 - 65}{2}

25 t^{2} + 20 t + 3 = - 1

0 = 4 x^{2} - 8 x + 3

2 x^{2} - 1 = 7

9 x^{2} = 12 x - 2

12 x^{2} - 92 x + 126 = 0

What are the solutions to the equation -m^2-7m-4=-2m^2 ?
The solutions to the equation -m^2-7m-4=-2m^2 are m=(7+sqrt(65))/2 ,m=(7-sqrt(65))/2
Find the zeros of -m^2-7m-4=-2m^2
The zeros of -m^2-7m-4=-2m^2 are m=(7+sqrt(65))/2 ,m=(7-sqrt(65))/2