What are the solutions to the equation (x)=2x^2+8x+11 ?

The solutions to the equation (x)=2x^2+8x+11 are x=-7/4+i(sqrt(39))/4 ,x=-7/4-i(sqrt(39))/4

Find the zeros of (x)=2x^2+8x+11

The zeros of (x)=2x^2+8x+11 are x=-7/4+i(sqrt(39))/4 ,x=-7/4-i(sqrt(39))/4

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(x) = 2 x^{2} + 8 x + 11

x = - \frac{7}{4} + i \frac{39}{4}, x = - \frac{7}{4} - i \frac{39}{4}

Solution steps

(x) = 2 x^{2} + 8 x + 11

Refine

x = 2 x^{2} + 8 x + 11

Switch sides

2 x^{2} + 8 x + 11 = x

Move

x

to the left side

2 x^{2} + 7 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 11}{2 \cdot 2}

Simplify

7^{2} - 4 \cdot 2 \cdot 11 : 39 i

x_{1, 2} = \frac{- 7 \pm 39 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 39 i}{2 \cdot 2}, x_{2} = \frac{- 7 - 39 i}{2 \cdot 2}

x = \frac{- 7 + 39 i}{2 \cdot 2} : - \frac{7}{4} + i \frac{39}{4}

x = \frac{- 7 - 39 i}{2 \cdot 2} : - \frac{7}{4} - i \frac{39}{4}

The solutions to the quadratic equation are:

x = - \frac{7}{4} + i \frac{39}{4}, x = - \frac{7}{4} - i \frac{39}{4}

- 5 = - \frac{1}{2} 9.8 x^{2} + 2 x

x, z^{2} = x^{2} y + 4.02

9 y^{2} = - 30 y - 25

x^{2} + 2 x - 76 = 4

94 - q = q^{2}

What are the solutions to the equation (x)=2x^2+8x+11 ?
The solutions to the equation (x)=2x^2+8x+11 are x=-7/4+i(sqrt(39))/4 ,x=-7/4-i(sqrt(39))/4
Find the zeros of (x)=2x^2+8x+11
The zeros of (x)=2x^2+8x+11 are x=-7/4+i(sqrt(39))/4 ,x=-7/4-i(sqrt(39))/4