What are the solutions to the equation 1/7 p^2= 5/7 p^2-20 ?

The solutions to the equation 1/7 p^2= 5/7 p^2-20 are p=sqrt(35),p=-sqrt(35)

Find the zeros of 1/7 p^2= 5/7 p^2-20

The zeros of 1/7 p^2= 5/7 p^2-20 are p=sqrt(35),p=-sqrt(35)

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\frac{1}{7} p^{2} = \frac{5}{7} p^{2} - 20

p = 35, p = - 35

Decimal

p = 5.91607 \dots, p = - 5.91607 \dots

Solution steps

\frac{1}{7} p^{2} = \frac{5}{7} p^{2} - 20

Move

\frac{5}{7} p^{2}

to the left side

- \frac{4}{7} p^{2} = - 20

Multiply both sides by

7

- 4 p^{2} = - 140

Divide both sides by

- 4

p^{2} = 35

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 35, p = - 35

2 x^{2} + 12 x - 3

4.9 t^{2} + 6 t + 2 = 0

x^{2} + 4 x - 12

y, x^{2} + 3 y^{2} - 4 x + 24 y = - 52

18 x - 6 = 9 x^{2}

What are the solutions to the equation 1/7 p^2= 5/7 p^2-20 ?
The solutions to the equation 1/7 p^2= 5/7 p^2-20 are p=sqrt(35),p=-sqrt(35)
Find the zeros of 1/7 p^2= 5/7 p^2-20
The zeros of 1/7 p^2= 5/7 p^2-20 are p=sqrt(35),p=-sqrt(35)