What are the solutions to the equation z^2+8z+15=0 ?

The solutions to the equation z^2+8z+15=0 are z=-3,z=-5

Find the zeros of z^2+8z+15=0

The zeros of z^2+8z+15=0 are z=-3,z=-5

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z^{2} + 8 z + 15 = 0

z = - 3, z = - 5

Solution steps

z^{2} + 8 z + 15 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

z_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 8 + 2}{2 \cdot 1}, z_{2} = \frac{- 8 - 2}{2 \cdot 1}

z = \frac{- 8 + 2}{2 \cdot 1} : - 3

z = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

z = - 3, z = - 5

11 y^{2} - 12 y + 4 = 6 y^{2}

x^{2} - 2 x - 2 = 0, x > 0

y, x^{2} y^{9} = 2

x^{2} - 10 x - 9

x^{2} - 10 x - 7

What are the solutions to the equation z^2+8z+15=0 ?
The solutions to the equation z^2+8z+15=0 are z=-3,z=-5
Find the zeros of z^2+8z+15=0
The zeros of z^2+8z+15=0 are z=-3,z=-5