What are the solutions to the equation 11b^2-6b+1=2b^2 ?

The solutions to the equation 11b^2-6b+1=2b^2 are b= 1/3

Find the zeros of 11b^2-6b+1=2b^2

The zeros of 11b^2-6b+1=2b^2 are b= 1/3

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11 b^{2} - 6 b + 1 = 2 b^{2}

b = \frac{1}{3}

Decimal Notation

b = 0.33333 \dots

Solution steps

11 b^{2} - 6 b + 1 = 2 b^{2}

Move

2 b^{2}

to the left side

9 b^{2} - 6 b + 1 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 \cdot 1 = 0

b_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 9}

b = \frac{- ( - 6 )}{2 \cdot 9}

\frac{- ( - 6 )}{2 \cdot 9} = \frac{1}{3}

b = \frac{1}{3}

The solution to the quadratic equation is:

b = \frac{1}{3}

2 w^{2} + 4 w = - 3

p^{2} - 10 p - 52 = 0

y, x^{2} + y^{3} = 4

5 x^{2} = 15 x

4 x^{2} + 57 = - 28 x

What are the solutions to the equation 11b^2-6b+1=2b^2 ?
The solutions to the equation 11b^2-6b+1=2b^2 are b= 1/3
Find the zeros of 11b^2-6b+1=2b^2
The zeros of 11b^2-6b+1=2b^2 are b= 1/3