What are the solutions to the equation roots 1-x-x^2 ?

The solutions to the equation roots 1-x-x^2 are x=-(1+sqrt(5))/2 ,x=(sqrt(5)-1)/2

Find the zeros of roots 1-x-x^2

The zeros of roots 1-x-x^2 are x=-(1+sqrt(5))/2 ,x=(sqrt(5)-1)/2

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roots

1 - x - x^{2}

x = - \frac{1 + 5}{2}, x = \frac{5 - 1}{2}

Solution steps

1 - x - x^{2}

The roots are the intercepts with the x-axis

(y = 0)

1 - x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 1 = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 5}{2 ( - 1 )} : - \frac{1 + 5}{2}

x = \frac{- ( - 1 ) - 5}{2 ( - 1 )} : \frac{5 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 5}{2}, x = \frac{5 - 1}{2}

(4 x - 2)^{2} + 14 = 0

- 3 x^{2} + 450 x - 875 = 0

2 m^{2} - 5 m - 3

0 = x^{2} - 3 x - 9

2 + 24.5 t - 4.9 t^{2} = 0

What are the solutions to the equation roots 1-x-x^2 ?
The solutions to the equation roots 1-x-x^2 are x=-(1+sqrt(5))/2 ,x=(sqrt(5)-1)/2
Find the zeros of roots 1-x-x^2
The zeros of roots 1-x-x^2 are x=-(1+sqrt(5))/2 ,x=(sqrt(5)-1)/2