What are the solutions to the equation 0=x^2-3x-9 ?

The solutions to the equation 0=x^2-3x-9 are x=(3+3sqrt(5))/2 ,x=(3-3sqrt(5))/2

Find the zeros of 0=x^2-3x-9

The zeros of 0=x^2-3x-9 are x=(3+3sqrt(5))/2 ,x=(3-3sqrt(5))/2

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0 = x^{2} - 3 x - 9

x = \frac{3 + 3 5}{2}, x = \frac{3 - 3 5}{2}

Decimal Notation

x = 4.85410 \dots, x = - 1.85410 \dots

Solution steps

0 = x^{2} - 3 x - 9

Switch sides

x^{2} - 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 9) = 35

x_{1, 2} = \frac{- ( - 3 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3 5}{2 \cdot 1} : \frac{3 + 3 5}{2}

x = \frac{- ( - 3 ) - 3 5}{2 \cdot 1} : \frac{3 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 3 5}{2}, x = \frac{3 - 3 5}{2}

2 + 24.5 t - 4.9 t^{2} = 0

4 x = 3 x^{2} - 7 x + 9

8 x^{2} - 17 x = 4 x^{2} + 13 x

(x) = x^{2} - 4 x + 3

9 x^{2} = 4 x + 1

What are the solutions to the equation 0=x^2-3x-9 ?
The solutions to the equation 0=x^2-3x-9 are x=(3+3sqrt(5))/2 ,x=(3-3sqrt(5))/2
Find the zeros of 0=x^2-3x-9
The zeros of 0=x^2-3x-9 are x=(3+3sqrt(5))/2 ,x=(3-3sqrt(5))/2