What are the solutions to the equation 4(x-2)^2=5 ?

The solutions to the equation 4(x-2)^2=5 are x=(sqrt(5))/2+2,x=-(sqrt(5))/2+2

Find the zeros of 4(x-2)^2=5

The zeros of 4(x-2)^2=5 are x=(sqrt(5))/2+2,x=-(sqrt(5))/2+2

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4 (x - 2)^{2} = 5

x = \frac{5}{2} + 2, x = - \frac{5}{2} + 2

Decimal Notation

x = 3.11803 \dots, x = 0.88196 \dots

Solution steps

4 (x - 2)^{2} = 5

Divide both sides by

4

(x - 2)^{2} = \frac{5}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = \frac{5}{4} : x = \frac{5}{2} + 2

Solve

x - 2 = - \frac{5}{4} : x = - \frac{5}{2} + 2

The solutions to the quadratic equation are:

x = \frac{5}{2} + 2, x = - \frac{5}{2} + 2

4 (x - 2)^{2} = 9

x^{2} - 2 x + 8 = 4 x

y, x^{2} y^{2} - 2 x^{2} y + x^{2} - 2 x + 1 = 0

x^{2} + 6 x = 7

0.000002 x^{2} - 0.06 x + 400 = 0

What are the solutions to the equation 4(x-2)^2=5 ?
The solutions to the equation 4(x-2)^2=5 are x=(sqrt(5))/2+2,x=-(sqrt(5))/2+2
Find the zeros of 4(x-2)^2=5
The zeros of 4(x-2)^2=5 are x=(sqrt(5))/2+2,x=-(sqrt(5))/2+2