What are the solutions to the equation 2x^2+8x+22=0 ?

The solutions to the equation 2x^2+8x+22=0 are x=-2+sqrt(7)i,x=-2-sqrt(7)i

Find the zeros of 2x^2+8x+22=0

The zeros of 2x^2+8x+22=0 are x=-2+sqrt(7)i,x=-2-sqrt(7)i

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2 x^{2} + 8 x + 22 = 0

x = - 2 + 7 i, x = - 2 - 7 i

Solution steps

2 x^{2} + 8 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 22}{2 \cdot 2}

Simplify

8^{2} - 4 \cdot 2 \cdot 22 : 47 i

x_{1, 2} = \frac{- 8 \pm 4 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4 7 i}{2 \cdot 2}, x_{2} = \frac{- 8 - 4 7 i}{2 \cdot 2}

x = \frac{- 8 + 4 7 i}{2 \cdot 2} : - 2 + 7 i

x = \frac{- 8 - 4 7 i}{2 \cdot 2} : - 2 - 7 i

The solutions to the quadratic equation are:

x = - 2 + 7 i, x = - 2 - 7 i

4 a^{2} + 120 a - 70520 = 0

x^{2} - 10 x + 25

2 x^{2} - 80 = - 12 x

4 x^{2} + 4 x + 1

(x - 3)^{2} = 121

What are the solutions to the equation 2x^2+8x+22=0 ?
The solutions to the equation 2x^2+8x+22=0 are x=-2+sqrt(7)i,x=-2-sqrt(7)i
Find the zeros of 2x^2+8x+22=0
The zeros of 2x^2+8x+22=0 are x=-2+sqrt(7)i,x=-2-sqrt(7)i