What are the solutions to the equation 3x^2+9x-27=0 ?

The solutions to the equation 3x^2+9x-27=0 are x=(3(sqrt(5)-1))/2 ,x=-(3(1+sqrt(5)))/2

Find the zeros of 3x^2+9x-27=0

The zeros of 3x^2+9x-27=0 are x=(3(sqrt(5)-1))/2 ,x=-(3(1+sqrt(5)))/2

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3 x^{2} + 9 x - 27 = 0

x = \frac{3 ( 5 - 1 )}{2}, x = - \frac{3 ( 1 + 5 )}{2}

Decimal Notation

x = 1.85410 \dots, x = - 4.85410 \dots

Solution steps

3 x^{2} + 9 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 ( - 27 )}{2 \cdot 3}

9^{2} - 4 \cdot 3 (- 27) = 95

x_{1, 2} = \frac{- 9 \pm 9 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 9 5}{2 \cdot 3}, x_{2} = \frac{- 9 - 9 5}{2 \cdot 3}

x = \frac{- 9 + 9 5}{2 \cdot 3} : \frac{3 ( 5 - 1 )}{2}

x = \frac{- 9 - 9 5}{2 \cdot 3} : - \frac{3 ( 1 + 5 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 5 - 1 )}{2}, x = - \frac{3 ( 1 + 5 )}{2}

6 x^{2} - x - 12 = 0

x^{2} = 12 + x

3 (2 x - 3)^{2} - 33 = - 3

12 x^{2} - 8 x + 1 = 0

x^{2} + 8 x + 20

What are the solutions to the equation 3x^2+9x-27=0 ?
The solutions to the equation 3x^2+9x-27=0 are x=(3(sqrt(5)-1))/2 ,x=-(3(1+sqrt(5)))/2
Find the zeros of 3x^2+9x-27=0
The zeros of 3x^2+9x-27=0 are x=(3(sqrt(5)-1))/2 ,x=-(3(1+sqrt(5)))/2