What are the solutions to the equation 3(2x-3)^2-33=-3 ?

The solutions to the equation 3(2x-3)^2-33=-3 are x=(sqrt(10)+3)/2 ,x=(-sqrt(10)+3)/2

Find the zeros of 3(2x-3)^2-33=-3

The zeros of 3(2x-3)^2-33=-3 are x=(sqrt(10)+3)/2 ,x=(-sqrt(10)+3)/2

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3 (2 x - 3)^{2} - 33 = - 3

x = \frac{10 + 3}{2}, x = \frac{- 10 + 3}{2}

Decimal Notation

x = 3.08113 \dots, x = - 0.08113 \dots

Solution steps

3 (2 x - 3)^{2} - 33 = - 3

Move

33

to the right side

3 (2 x - 3)^{2} = 30

Divide both sides by

3

(2 x - 3)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 10 : x = \frac{10 + 3}{2}

Solve

2 x - 3 = - 10 : x = \frac{- 10 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{10 + 3}{2}, x = \frac{- 10 + 3}{2}

12 x^{2} - 8 x + 1 = 0

x^{2} + 8 x + 20

x, x^{2} + 2 x + 1 - m^{2} = 0

r^{2} = - 96

x^{2} - 8 x + 65 = 0

What are the solutions to the equation 3(2x-3)^2-33=-3 ?
The solutions to the equation 3(2x-3)^2-33=-3 are x=(sqrt(10)+3)/2 ,x=(-sqrt(10)+3)/2
Find the zeros of 3(2x-3)^2-33=-3
The zeros of 3(2x-3)^2-33=-3 are x=(sqrt(10)+3)/2 ,x=(-sqrt(10)+3)/2